4×6 Polybius Rectangle (I=J and U=V)

70 84 61 60 73 83 83 83 83 60 70 80 94 93 83 83 83 83 80 73 70 64 85 63 93 63 70 70 70 70 70 70 70 72 72 83 60 82 74 71 73 63 72 72 85 83 80 74 63 74 74 74 74 74 80 63 73 74 70 82 60 63 72 70 64 71 63 64 65 63 84 74 80 80 80 80 80 63 62 63 73 70 64 63 95 61 61 61 61 95 70 64 71 61 61 65 80 83 73 61 84 61 70 80 70 64 72 85 83 94 83 63 60 62 62 62 81 81 81 75 75 75 70 70 70 70 72 85 70 64 90

Contributed by Lee Morgenstern

Solved by:  

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       The following cryptogram is slightly more complex than a conventional simple substitution, where one letter stands for another letter. Determining the method is part of the challenge. You need to figure out what type of cryptogram this is, then solve it. The word breaks and punctuation have been removed.

Solved by:   Lee Morgenstern

       The following cryptogram is slightly more complex than a conventional simple substitution, where one letter stands for another letter. Determining the method is part of the challenge. You need to figure out what type of cryptogram this is, then solve it.
       The word breaks and punctuation have been removed. The spaces between groups and the line breaks are significant.
       It is within the range of any experienced amateur cryptographer, but it is not intended for the novice.

-=-=-- --=-- ---=- =--=- =-=-- =-=== ===== --==- ==--- =-=-- ==--= ==-==
====-= --=-= ---=- ==--= -=--- =-=-- ==-== =---- --=== -=--= -=--- =--==
==-==- =-=== ===-= -=-== ===-= -==-- ---=- =-=-- ==-=- --=-- =-=-= -=-==
--==== -==-= -=--= --=== -=--= --==- =-=-= -==-= ==--- =-==- ---=- ---=-
-=-==- ==--- --=-= --==- =-=== --=== -=--= =---- --=== --==- =-=-= -=--=
-----= =-==- ====- ==--= ---=- =-=-- ----- =-==- -=--= -=-== ===-= -=---
====-= --=== -=-== ==-== =-=-= --==- ===-- =-==- ==--- ==-=- --=-= --==-
-=-=== -=-== ==-== ====- =-=-- =-=-= --==- ---=- =-==- ----= =-==- ====-
----=- --=-= --=-= -=--= =-=== -==-- ==--= ==--- =-=-= -==-= --==- ==---
=--==- =-=-= ===-= -=--= --=== -=--- --=-= -==-= -=-== ==--- =-==- ==--=
=--=-= ==-== -=--= ==-=- ==--= -=--- =-=-- --=-- ----= -=-== -=-=- ==--=
----=- =-==- ----= =-==- ====- ---=- --=-= --=-= ====- =-=-- ===-= ---=-
=-=--= --=== -=--= ==-== ===-= -=--- ====- ==-== =-==- ==-=- --=== -=---

       The following cryptogram is a complete columnar transposition, one of the standard types of elementary ciphers published in The Cryptogram. It is easily solved by paper and pencil methods.
       If you are not familiar with this type, CLICK HERE for the basics.
       In the cryptograms from this point forward the word breaks and punctuation are not shown. By convention, the letters have been grouped into fives. Neither the spaces nor the line breaks have any significance.

       This is an incomplete columnar transposition, somewhat harder than the preceding, but it still can be solved by paper and pencil methods.
       If you are not familiar with this type, CLICK HERE for the basics.

       The following cryptogram was not done by any of the standard elementary methods. Determining the method is part of the challenge. You need to figure out what type of cryptogram this is, then solve it.
       It is within the range of any experienced amateur cryptographer, but it is not intended for the novice.

       In this unusual cryptogram the message has been encrypted by a 2-step process. Each group of 6 letters represents an arithmetic expression. Each of the digits 0 to 9 and the math signs + - × and ÷ have been replaced by letters. Each letter represents the same digit or sign throughout. When each of the 14 arithmetic expressions is evaluated left to right it will yield one letter of the 14-letter message according to the rule A=1, B=2, C=3, etc.
       For example, if the 6-letter group TBNUGF happened to represent the expression 14-8×2 then it would evaluate to 12 and represent the letter L.

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